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Linear Inequalities

The length of a rectangle is 5cm less than twice it's width. If the perimeter of the rectangle is no more than 80cm, what are the maximum possible dimensions?​

User Vyke
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9.2k points

2 Answers

1 vote

Answer:15 cm and 25 cm

Explanation:

User Tbhartman
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8.6k points
6 votes

Answer:

15 cm and 25 cm

Explanation:

First let's mark the width with the letter b, and the length with a:

width: b

length: a = (2b - 5)

Then we have an inequality (P = 2a + 2b):

2 × (2b - 5) + 2b ≤ 80

4b - 10 + 2b ≤ 80

6b ≤ 80 + 10

6b ≤ 90 / : 6

b ≤ 15

a ≤ 2 × 15 - 5

a ≤ 25

User Gavin Wright
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9.3k points