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a b and c are positive intergers a:b = 3:8 and b:c= 6:11 work out the smallest possible value of a b and c

User Gwt
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Answer:

We can use ratios to set up a system of equations and solve for a, b, and c. Since a:b = 3:8, we can write:

a = 3x

b = 8x

Similarly, since b:c = 6:11, we can write:

b = 6y

c = 11y

Now we have two expressions for b, so we can set them equal to each other and solve for y:

8x = 6y

y = 4x/3

Substituting y back into the expression for c, we get:

c = 11y = 44x/3

To find the smallest possible values of a, b, and c, we want to choose values of x that are as small as possible while still being positive integers. Since x must be a multiple of 3 (because a = 3x is a multiple of 3), let's try x = 3. Then we get:

a = 3x = 9

b = 8x = 24

c = 44x/3 = 44

So the smallest possible values of a, b, and c are 9, 24, and 44, respectively.

Explanation:

User Georgemp
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