Question

What is the equation of a line that is perpendicular to the line y = −3x + 2 and passes through the point (6, 8)?

A. y=3x+2
B. y=3x-10
C. y=1/3x+2
D. y=1/3x+6

Answer 1

D

Explanation:

The gradient of the line y = -3x+2 is -3 so the gradient of the perp line will be ⅓

Now y=mx+c

8 = (⅓×6) + c

C = 6

Y = ⅓x + 6