What is the equation of a line that is perpendicular to the line y = −3x + 2 and passes through the point (6, 8)? A. y=3x+2 B. y=3x-10 C. y=1/3x+2 D. y=1/3x+6

Question

asked Oct 12, 2024 67.9k views

1 Answer

Magda · Answer 1 · 2024-10-16T19:24:55+0000

Answer:

D

Explanation:

The gradient of the line y = -3x+2 is -3 so the gradient of the perp line will be ⅓

Now y=mx+c

8 = (⅓×6) + c

C = 6

Y = ⅓x + 6