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Write the net ionic equation for the following molecular equation. 2FeCl3(aq) + 3(NH4)2CO3(aq) Fe2(CO3)3(s) + 6NH4Cl(aq)

User Chrisg
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The first step is to write the complete ionic equation by breaking apart all soluble ionic compounds into their constituent ions:

2Fe³⁺(aq) + 6Cl⁻(aq) + 6NH₄⁺(aq) + 3CO₃²⁻(aq) → Fe₂(CO₃)₃(s) + 6NH₄⁺(aq) + 6Cl⁻(aq)

Next, we cancel out any spectator ions that appear on both sides of the equation, which in this case is the 6NH₄⁺ and the 6Cl⁻.

The resulting net ionic equation is:

2Fe³⁺(aq) + 3CO₃²⁻(aq) → Fe₂(CO₃)₃(s)

Therefore, the net ionic equation for the given molecular equation is:

2Fe³⁺(aq) + 3CO₃²⁻(aq) → Fe₂(CO₃)₃(s)


User Bwt
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