The first step is to write the complete ionic equation by breaking apart all soluble ionic compounds into their constituent ions:
2Fe³⁺(aq) + 6Cl⁻(aq) + 6NH₄⁺(aq) + 3CO₃²⁻(aq) → Fe₂(CO₃)₃(s) + 6NH₄⁺(aq) + 6Cl⁻(aq)
Next, we cancel out any spectator ions that appear on both sides of the equation, which in this case is the 6NH₄⁺ and the 6Cl⁻.
The resulting net ionic equation is:
2Fe³⁺(aq) + 3CO₃²⁻(aq) → Fe₂(CO₃)₃(s)
Therefore, the net ionic equation for the given molecular equation is:
2Fe³⁺(aq) + 3CO₃²⁻(aq) → Fe₂(CO₃)₃(s)