Question

The work, W (in joules), done when lifting an object is jointly proportional to the product of the mass, m (in kilograms), of the object and the height, h (in meters), that the object is lifted. The work done when a 100-kilogram object is lifted 1.5 meters above the ground is 2116.8 joules.

Answer 1

The constant of variation in the given problem is 9.8

GIVEN

w = 2,116.8

m = 120

h = 1.8

SOLUTION

w=kmh

2116.8 = k(120)(1.8)

2116.8=216k

9.8=k