Question

A coupon-printing machine at the checkout of a grocery store prints one food coupon and one pharmacy coupon for each customer. The value of each coupon is randomly selected from $0.25, $0.30, $0.40, $0.45, or $0.50. What is the probability that a customer receives a $0.25 food coupon and a $0.40 pharmacy coupon at the checkout?

Answer 1

In this case, we are given a coupon-printing machine at the checkout of a grocery store prints one food coupon and one pharmacy coupon for each customer: $0.25, $0.30, $0.40, $0.45, or $0.50. It is asked in the problem to give the probability that a customer receives a $0.25 food coupon and a $0.40 pharmacy coupon at the checkout. Since the customer chose the $0.25 food coupon and a $0.40 pharmacy coupon,

Then the probability is 2/5. this is equal to 40%.

Answer 2

the answer will be: C. 1/25

Explanation:

There are five possible values for each coupon, so there are 5 x 5 = 25 possible combinations of food and pharmacy coupons. Each combination is equally likely, so the probability of getting any particular combination is 1/25.

There is only one combination that gives a $0.25 food coupon and a $0.40 pharmacy coupon, so the probability of getting this combination is 1/25.

Therefore, the probability that a customer receives a $0.25 food coupon and a $0.40 pharmacy coupon at the checkout is 1/25 or 0.04 (4%).