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x^(2) logx=10xx^(2)x^2logx = 10x2

User Gedii
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\begin{array}{llll} \textit{Logarithm Cancellation Rules} \\\\ log_a a^x = x\qquad \qquad \stackrel{ \textit{we'll be using this one} }{a^(log_a (x))=x} \end{array} \\\\[-0.35em] ~\dotfill\\\\ x^2\log(x)=10x^2\implies \log(x)=\cfrac{10x^2}{x^2}\implies \log(x)=10 \\\\\\ \log_(10)(x)=10\implies 10^{\log_(10)(x)}=10^(10)\implies x=10^(10)\implies x=10000000000

User Thisdotnull
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