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Single displacement or NR (no reaction)
Lead (II) + Nitric acid → ? + ? (Product)

User Aerioeus
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1 Answer

6 votes

Answer:

There will be a displacement reaction, with Lead (II) + Nitric acid → Lead (II) Nitrate + Hydrogen.

Step-by-step explanation:

In the reactivity series, Lead is more reactive than Hydrogen (within the nitric acid) meaning that it will displace it forming Lead(II) Nitrate and Hydrogen gas.

This leads to the equation:

Lead (II) + Nitric acid → Lead (II) Nitrate + Hydrogen

Pb (s) + 2HNO3 (aq) → Pb(NO3)2 (aq) + H2 (g)

If the nitric acid was dilute (which the question does not mention, so shouldn't be mentioned) however it will form:

Lead (II) + Nitric acid → Lead (II) Nitrate + Nitrogen Dioxide + Water

Pb (s) + 4HNO3 (aq) → Pb(NO3)2 (aq) + 2NO2 (g) + 2H2O (l)

Hope this helps!!!

User Mario David
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