Answer:
There will be a displacement reaction, with Lead (II) + Nitric acid → Lead (II) Nitrate + Hydrogen.
Step-by-step explanation:
In the reactivity series, Lead is more reactive than Hydrogen (within the nitric acid) meaning that it will displace it forming Lead(II) Nitrate and Hydrogen gas.
This leads to the equation:
Lead (II) + Nitric acid → Lead (II) Nitrate + Hydrogen
Pb (s) + 2HNO3 (aq) → Pb(NO3)2 (aq) + H2 (g)
If the nitric acid was dilute (which the question does not mention, so shouldn't be mentioned) however it will form:
Lead (II) + Nitric acid → Lead (II) Nitrate + Nitrogen Dioxide + Water
Pb (s) + 4HNO3 (aq) → Pb(NO3)2 (aq) + 2NO2 (g) + 2H2O (l)
Hope this helps!!!