Answer:
289.8 grams.
Step-by-step explanation:
When the ice cube melts, it absorbs heat from the water in the dog's dish and undergoes a phase change from solid to liquid at 0.00 °C. The heat absorbed by the ice cube can be calculated using the formula:
Q = m * L
where Q is the heat absorbed, m is the mass of the ice cube, and L is the heat of fusion of water (which is 334 J/g). The heat absorbed by the ice cube is then equal to the heat released by the water, which can be calculated using the formula:
Q = m * c * ΔT
where m is the mass of the water, c is the specific heat capacity of water (which is 4.184 J/g·°C), and ΔT is the change in temperature of the water.
Setting the two formulas equal to each other, we get:
m * L = m * c * ΔT
Solving for m, we get:
m = (c * ΔT * m_water) / L
where m_water is the mass of the water in the dog's dish.
Substituting the given values, we get:
m = (4.184 J/g·°C * (27.0 °C - 18.0 °C) * 2500.0 g) / (334 J/g)
m ≈ 289.8 g
Therefore, the mass of the ice cube was approximately 289.8 grams.