Question

a jar contains 30 coins, all dimes and quarters. the value of the coins is $4.80. how many of each coin is in the jar

Answer 1

Let x be the number of dimes in the jar.

Then the number of quarters in the jar would be 30 - x.

The total value of the dimes in the jar would be 0.10x, and the total value of the quarters would be 0.25(30 - x) = 7.50 - 0.25x.

We know that the total value of the coins is $4.80, so we can set up the equation:

0.10x + 7.50 - 0.25x = 4.80

Simplifying and solving for x, we get:

0.15x = 2.70

x = 18

Therefore, there are 18 dimes and 30 - 18 = 12 quarters in the jar.

Explanation:

Answer 2

Explanation:

1 quarter = 25 cents

1 dime = 10 cents

Let

q = the number of quarters, q>=0, q is integer

d = the number of dimes, d>=0, d is integ

30 coins totaling $4.80 = 480 cents:

q + d = 30

25q + 10d = 480

q = 12 quarters

d = 18 dimes

12 quarters and 18 dimes.