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a jar contains $5.55. there are three times as many dimes as nickels and twice as many quarters as dimes. how many of each coin is in the jar?

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Answer:

Let's start by assigning variables to represent the number of nickels, dimes, and quarters in the jar.

Let x be the number of nickels.

Then the number of dimes is 3 times as many as nickels, so the number of dimes is 3x.

And the number of quarters is twice as many as dimes, so the number of quarters is 2(3x) = 6x.

We know that the total amount of money in the jar is $5.55, which is equal to:

0.05x (for the value of the nickels) + 0.10(3x) (for the value of the dimes) + 0.25(6x) (for the value of the quarters)

Simplifying this expression, we get:

0.05x + 0.30x + 1.50x = 5.55

Combining like terms, we have:

1.85x = 5.55

Dividing both sides by 1.85, we get:

x = 3

So there are 3 nickels in the jar.

Using this value, we can find the number of dimes and quarters:

Number of dimes = 3x = 3(3) = 9

Number of quarters = 6x = 6(3) = 18

Therefore, there are 3 nickels, 9 dimes, and 18 quarters in the jar.

Explanation:

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