Question

Each time Caroline goes shopping she decides whether or not to buy fruit. The probability that she does buy fruit is 0.4. Independently, she then decides whether or not to buy a CD, with a probability of 0.6 that she does buy a CD. Work out the probability that she buys fruit or buys a CD or both.​

Answer 1

To work out the probability that Caroline buys fruit or buys a CD or both, you can use the formula:

P(A or B) = P(A) + P(B) - P(A and B)

where A and B are events.

In this case, A is the event that Caroline buys fruit and B is the event that Caroline buys a CD.

The probability that Caroline buys fruit is 0.4 and the probability that Caroline buys a CD is 0.6.

To find the probability that Caroline buys fruit and a CD, you can multiply the probabilities of the two events:

P(A and B) = P(A) x P(B) = 0.4 x 0.6 = 0.24

Therefore, the probability that Caroline buys fruit or buys a CD or both is:

P(A or B) = P(A) + P(B) - P(A and B) = 0.4 + 0.6 - 0.24 = 0.76

So, the probability that Caroline buys fruit or buys a CD or both is 0.76 .