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Find length of side of Rhombous whose diagonals are 6cm and 12cm​

2 Answers

4 votes

Explanation:

We know that diagonals of a rhombus perpendicularly bisect each other.

Therefore

Let side of rhombus be 'a' , then


{a}^(2) =( (d1)/(2) )^(2) + ( (d2)/(2) ) + = (12)/(2)^(2) + ( (6)/(2)) ^(2) = 36 + 9 \\ \\ a ^(2) = 45 = a = \sqrt[3]{5}

User Drmuelr
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1 vote

Answer:

Explanation:

Find length of side of Rhombous whose diagonals are 6cm and 12cm​-example-1
User Janechii
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7.2k points