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boat travels at velocity 45 mph in a direction 20.0osouth of west. Find the components of the boat's velocity

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Answer:

Step-by-step explanation:

We can break down the velocity of the boat into its components using trigonometry.

Let's call the velocity of the boat "v" and let the angle between the boat's velocity vector and the westward direction be represented by θ, where θ = 20.0°.

The x-component of the velocity can be found using cosine:

vx = v * cos(θ)

vx = 45 mph * cos(20.0°)

vx = 42.58 mph (rounded to two decimal places)

The y-component of the velocity can be found using sine:

vy = v * sin(θ)

vy = 45 mph * sin(20.0°)

vy = 15.34 mph (rounded to two decimal places)

Therefore, the components of the boat's velocity are vx = 42.58 mph west and vy = 15.34 mph south.

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