205k views
5 votes
What is the osmotic pressure of a 0.150 M aqueous glycerol (molar mass mass = 92.09 g) solution at 35°C?​

1 Answer

2 votes
π = 3.58 atm

Explained:

To calculate the osmotic pressure of a solution, we can use the equation:

π = MRT

where π is the osmotic pressure, M is the molarity of the solution, R is the gas constant, and T is the temperature in Kelvin.

First, we need to convert the temperature of 35°C to Kelvin:

T = 35°C + 273.15 = 308.15 K

Next, we need to calculate the molarity of the solution. The molarity (M) is defined as the number of moles of solute per liter of solution:

M = moles of solute / liters of solution

The molar mass of glycerol is 92.09 g/mol. To find the number of moles of glycerol in 1 liter of a 0.150 M solution, we can use the following equation:

moles of glycerol = M x liters of solution

moles of glycerol = 0.150 mol/L x 1 L = 0.150 mol

Now we can calculate the osmotic pressure using the formula:

π = MRT

π = (0.150 mol/L) x (0.0821 L atm/mol K) x (308.15 K)

π = 3.58 atm

Therefore, the osmotic pressure of a 0.150 M aqueous glycerol solution at 35°C is 3.58 atm.
User Tudmotu
by
8.4k points