Question

A boat pulls an inner tube behind it using a rope. The rope exerts a force 155 N on the inner tube at an angle of 5.88 above the horizontal. What are the horizontal and vertical components of this force?

Answer 1

The horizontal and vertical components of the 155 N force on the inner tube are 153.79 N and 15.85 N, respectively, calculated using trigonometric functions.

Step-by-step explanation:

The horizontal and vertical components of a force can be determined by using trigonometry. Given that a rope exerts a force of 155 N on an inner tube at an angle of 5.88 degrees above the horizontal, we can calculate the components as follows:

• The horizontal component (Fx) is given by Fx = F * cos(θ), where F is the force and θ is the angle. Using the values provided, Fx = 155 N * cos(5.88°).
• The vertical component (Fy) is given by Fy = F * sin(θ). Therefore, Fy = 155 N * sin(5.88°).

Carrying out the calculations:

• Horizontal component (Fx) is approximately 153.79 N
• Vertical component (Fy) is approximately 15.85 N

Thus, the horizontal component of the force is 153.79 N and the vertical component is 15.85 N.

Answer 2

154 N horizontal (to the right) 15.9 N vertical (up)

Step-by-step explanation:

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