44,626 views
32 votes
32 votes
DB is perpendicular to AE at C, AB is congruent to DE, and C is the midpoint of AE. Prove DE is parallel to AB

DB is perpendicular to AE at C, AB is congruent to DE, and C is the midpoint of AE-example-1
User Paul Hildebrandt
by
2.5k points

1 Answer

22 votes
22 votes

1.
\overline{DB} is perpendicular to
\overline{AE} at
C (given)

2.
\angle ACB and
\angle DCB are right angles (perpendicular lines form right angles)

3.
\triangle ACB and
\triangle DCE are right triangles (a triangle with a right angle is a right triangle)

4.
C is the midpoint of
\overline{AE} (given)

5.
\overline{AC} \cong \overline{CE} (definition of midpoint)

6.
\overline{AB} \cong \overline{DE} (given)

7.
\triangle ACB \cong \triangle ECB (HL)

8.
\angle BAC \cong \angle DEC (CPCTC)

9.
\overline{DE} \parallel \overline{AB} (converse of alternate interior angles theorem)

User Joel Joseph
by
3.0k points