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4 votes
A motorcycle travels, in one direction only, with an average speed of 916.66 m/min during the first 30 minutes of its travel and 900 m/min during the next 20 minutes.

Calculate (Units must be in units of the international system):
a. The total distance traveled.
b. The average speed.

User AFOC
by
8.5k points

1 Answer

4 votes

Step-by-step explanation:

a. To calculate the total distance traveled, we need to find the distance traveled during the first 30 minutes and the distance traveled during the next 20 minutes, and then add them up.

During the first 30 minutes:

distance = speed × time

distance = 916.66 m/min × 30 min

distance = 27,499.8 meters

During the next 20 minutes:

distance = speed × time

distance = 900 m/min × 20 min

distance = 18,000 meters

Total distance traveled:

distance = 27,499.8 meters + 18,000 meters

distance = 45,499.8 meters

Therefore, the total distance traveled is 45,499.8 meters.

b. To calculate the average speed, we need to divide the total distance traveled by the total time taken.

Total time taken:

time = 30 min + 20 min

time = 50 min

Average speed:

speed = distance ÷ time

speed = 45,499.8 meters ÷ 50 min

speed = 909.996 m/min

Therefore, the average speed is 909.996 m/min.

User Preetika
by
8.4k points
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