Answer:
= 87.98 g
Explanation:
The balanced chemical equation for the decomposition of calcium carbonate is:
CaCO3(s) → CaO(s) + CO2(g)
According to the equation, one mole of CaCO3 produces one mole of CaO and one mole of CO2.
First, we need to calculate the number of moles of CaO produced from the decomposition of 200 g of CaCO3:
molar mass of CaCO3 = 40.08 g/mol + 12.01 g/mol + 3(16.00 g/mol) = 100.09 g/mol
moles of CaCO3 = mass / molar mass = 200 g / 100.09 g/mol = 1.999 mol
From the balanced equation, we see that the number of moles of CaO produced is equal to the number of moles of CaCO3 decomposed. Therefore, we have:
moles of CaO = 1.999 mol
Now we can use the mole ratio between CaO and CO2 to calculate the number of moles of CO2 produced:
1 mol CaO : 1 mol CO2
moles of CO2 = moles of CaO = 1.999 mol
Finally, we can convert the number of moles of CO2 to grams using its molar mass:
molar mass of CO2 = 12.01 g/mol + 2(16.00 g/mol) = 44.01 g/mol
mass of CO2 = moles of CO2 x molar mass of CO2 = 1.999 mol x 44.01 g/mol = 87.98 g
Therefore, 200 g of calcium carbonate produces approximately 88 g of carbon dioxide.