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What are the approximate solutions of 2x^2 - x + 10 = 0?

-2, 2.5

-1.97, 2.47

-2.5, 2

No solution

1 Answer

6 votes

The quadratic equation 2x^2 - x + 10 = 0 can be solved using the quadratic formula, which is:

x = [-b ± sqrt(b^2 - 4ac)] / 2a

Here, a = 2, b = -1, and c = 10. Substituting these values, we get:

x = [-(-1) ± sqrt((-1)^2 - 4(2)(10))] / 2(2)

x = [1 ± sqrt(1 - 80)] / 4

x = [1 ± sqrt(-79)] / 4

Since the square root of a negative number is not a real number, there are no real solutions to this equation. Therefore, the answer is "No solution".

User Charma
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