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write an exponetial fuction given an intial value of 50 and a growlth of 1. 2

User Tendi
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\qquad \textit{Amount for Exponential Growth} \\\\ A=P(1 + r)^t\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &50\\ r=rate\to 20\%\to (20)/(100)\dotfill &0.2\\ t=\textit{elapsed time} \end{cases} \\\\\\ A = 50(1 + 0.2)^(t) \implies \boxed{A =50(1.2)^t}

User Errx
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