Answer: 30 Child tickets 6 Adult tickets.
Explanation:
Set up your system of equations to solve.
36 tickets are purchased, meaning a number of child tickets, and a different number of adult tickets add up to 36. We can write this as x+y=36.
The price of the tickets add up to 252 dollars. We can write this as 6 (the child price) times x + 12 (the adult price) times y = 252
So, x+y=36 and 6x+12y=252.
I will solve this using the substitution method.
So, first, we need to isolate a variable, I will choose the first equation to do so.
x+y=36 ---> x=36-y
Now, plug the value of x into the second equation.
6(36-y)+12y=252.
Distribute.
216-6y+12y=252
Combine like terms.
216+6y=252.
Subtract 216 from both sides.
6y=36
Divide by 6 on both sides.
y=6
Now plug this value of y into the previous equation to get x.
x+6=36
Subtract 6 from both sides.
x=30
Remember x was children's tickets and y was adult tickets. (It is better to use variables like C and A in this case).