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A force of 6. 0 Newtons is applied to a block at rest on a horizontal frictionless surface over a 7. 0 meter span. How much energy is gained by the block?

a) 3. 0 m/s

b) 7. 0 m

c) 42 J

d) 6. 0 N

1 Answer

5 votes

Answer:


\huge\boxed{\sf E = 42 \ J}

Step-by-step explanation:

Given data:

Force = F = 6 N

Distance = d = 7 m

Required:

Energy = E = ?

Formula:

Here, Energy is gained in the form of work done. So, the formula will be:

E = Fd

Solution:

Put the given data in the above formula.

E = (6)(7)

E = 42 J


\rule[225]{225}{2}

User Parag Bhayani
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