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What percent of zinc in a 25.5 g sample of Zn³(PO4)?​
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What percent of zinc in a 25.5 g sample of Zn³(PO4)?​

User Stephen Ngethe
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1 Answer

3 votes

Step-by-step explanation:

From periodic table:

Zn = 65.38 gm/mole X 3 =196.14

P= 30.974

O = 15.999 X 4 =63.996

Total mole wt = 291.11 gm of which 196.14 is Zn

196.14 / 291.11 x 100% = 67% Zn

(NOTE that the sample mass of 25.5 g is irrelevant)

User Loudiyimo
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