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Hailey invested $940 with an interest rate of 8.25 % that is compounded quarterly and Justin invested $940 with an interest rate of 7.625% that is compounded monthly

To the nearest dollar, how much money would Hailey have in her account when Justin's money has tripled in value?

1 Answer

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To solve this problem, we need to first determine how long it will take for Justin's money to triple in value. We can use the formula for compound interest:

A = P(1 + r/n)^(nt)

where:

A = the final amount

P = the principal (initial amount)

r = the annual interest rate (as a decimal)

n = the number of times the interest is compounded per year

t = the number of years

For Justin, we have:

P = $940

r = 0.07625

n = 12 (monthly compounding)

t = unknown

We want to solve for t when A = 3P = $2820. We can rearrange the formula and plug in the values:

A = P(1 + r/n)^(nt)

3P = P(1 + r/n)^(nt)

3 = (1 + 0.07625/12)^(12t)

ln(3) = 12t * ln(1 + 0.07625/12)

t = ln(3) / (12 * ln(1 + 0.07625/12))

t ≈ 15.8 years

So it will take Justin about 15.8 years for his money to triple in value.

Now we can use the same formula to find how much money Hailey will have in her account after 15.8 years:

P = $940

r = 0.0825

n = 4 (quarterly compounding)

t = 15.8

A = P(1 + r/n)^(nt)

A = $940(1 + 0.0825/4)^(4*15.8)

A ≈ $3501

Therefore, Hailey will have about $3,501 in her account when Justin's money has tripled in value

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