Answer:
M = 0.011 mol/L
Step-by-step explanation:
Molarity = n/V,n: No. of molesV: volume in litersn of KMnO4 (Molar mass = 158 g/mol) = 0.435/158 = 0.00275 molesMolarity (M) = 0.00275/0.25 = 0.011 mol/L
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