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3 votes
The length of a

rectangular poster is 5 more inches than two
times its width. The area of the poster is 33 square inches. Solve
for the dimensions (length and width) of the poster.

User Jjohn
by
8.3k points

1 Answer

2 votes

Answer:

width is 3 inches, length is 11 inches.

Explanation:

Let l be the length and w be the width.

We have:


l = 2w + 5


(2w + 5)(w) = 33


2 {w}^(2) + 5w = 33


2 {w}^(2) + 5w - 33 = 0


(w - 3)(2w + 11) = 0


w = 3


l = 2(3) + 5 = 11

User Jackxujh
by
8.3k points

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