Question

A 3.1-mol sample of KCIO3 was decomposed according to the equation

2KCIO3(s)→ 2KC1(s) + 302(g)
How many moles of O₂ are formed assuming 100% yield?
a) 2.1 mol
b) 3.1 mol
c) 2.6 mol
Od) 4.7 mol
e) 1.6 mol

Answer 1

It's (d) 4.65 ≃ 4.7

Step-by-step explanation:

By understanding that a mole is the unit of amount of substance that equals Avogadro's number (
`N_a` = 6.022*10^23)

we make a ratio of moles as below:

2KClO3 --> 2KCl + 3O2
2 : 2 : 3
3.1 : ? : ?

part value = 3.1 / 2 = 1.55

number of moles of O2 yielded from this reaction = 1.55 * 3 = 4.65 moles