50.1k views
3 votes
Write the slope-intercept form of the equation of the line that is perpendicular to AB and passes through

Point X. Show all work for full credit.
A
(-10, 8)
-10
-8
X
(-5, 10)
-6
-4 -2
YA
10
8
4
2 B
-2
4
6
-8
-10
(2, 3)
2
4
6 8 10
X
A

1 Answer

1 vote

Answer:

To find the slope of line AB, we use the slope formula:

slope of AB = (yB - yA) / (xB - xA)

where A = (-10, 8) and B = (2, 3).

slope of AB = (3 - 8) / (2 - (-10)) = -5/12

The slope of a line perpendicular to AB will have a negative reciprocal slope, so its slope will be 12/5.

Using the slope-intercept form of the equation of a line:

y = mx + b

where m is the slope and b is the y-intercept, we can find the equation of the line that passes through point X (-5, 10) and has a slope of 12/5.

10 = (12/5)(-5) + b

10 = -24/5 + b

b = 74/5

Therefore, the equation of the line that is perpendicular to AB and passes through point X is:

y = (12/5)x + 74/5

User Zoplonix
by
8.4k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories