Question

a man sets out to travel from A to C via B. from A he travel a distance of 8km on a bearing of north 30°east to B. from B he travel a further 6km due east. calculate how far c is from north of A, east of A.​

Answer 1

D is how far north C is from A
DC is how Far East C is from A
To find AD:
Using Pythagorean’ theorem
AD= 3Cos30
= 3*0.866
=6.9km
… C is 6.9km north of A
11) DC = DB+BC
BC=6km
DB=?
DB= 8sin30
=8*0.5
=4km
DC=8+4=10km
… C is 10km east of A