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Ammonium phosphate ((NH4)3PO4) is an important ingredient in many fertilizers. It can be made by reacting phosphoric acid (H3PO4) with ammonia (NH3).

What mass of ammonium phosphate is produced by the reaction of 7.73 g of ammonia?

User Moby Disk
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Answer:

= 22.51 g of ammonium phosphate

Explanation:

The balanced chemical equation for the reaction between phosphoric acid and ammonia to form ammonium phosphate is:

H3PO4 + 3 NH3 → (NH4)3PO4

From the equation, we can see that 3 moles of ammonia react with 1 mole of phosphoric acid to produce 1 mole of ammonium phosphate.

To determine the mass of ammonium phosphate produced from 7.73 g of ammonia, we need to first calculate the number of moles of ammonia, and then use the mole ratio from the balanced equation to find the number of moles of ammonium phosphate. Finally, we can convert the number of moles of ammonium phosphate to its mass using its molar mass.

The molar mass of NH3 is 17.03 g/mol, and the molar mass of (NH4)3PO4 is 149.09 g/mol.

Number of moles of NH3 = mass / molar mass = 7.73 g / 17.03 g/mol = 0.453 mol

From the balanced equation, 3 moles of NH3 react to form 1 mole of (NH4)3PO4.

Number of moles of (NH4)3PO4 = 0.453 mol NH3 / 3 mol NH3/mol (NH4)3PO4 = 0.151 mol (NH4)3PO4

Mass of (NH4)3PO4 = number of moles x molar mass = 0.151 mol x 149.09 g/mol = 22.51 g

Therefore, 7.73 g of ammonia reacts to form 22.51 g of ammonium phosphate.
User Mager
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