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Among 300 elementary school students,

258 said they like chocolate ice cream, 142
like vanilla ice cream and 102 like both.
Find the probability that a randomly
selected student likes:
A. Vanilla ice cream or chocolate ice
cream, but not both.
B. Neither of the 2 flavors.
C. Vanilla ice cream but not chocolate ice
cream.

User LiamHT
by
7.9k points

1 Answer

0 votes

To solve this problem, we can use the formula for probability:

Probability = (Number of favorable outcomes) / (Total number of outcomes)

A. To find the probability that a student likes vanilla or chocolate ice cream, but not both, we need to subtract the number of students who like both from the total number of students who like vanilla or chocolate:

Number of students who like vanilla or chocolate = 258 + 142 = 400

Number of students who like both = 102

Number of students who like only vanilla or only chocolate = 400 - 102 = 298

Probability = 298/300 = 0.9933

B. To find the probability that a student likes neither vanilla nor chocolate ice cream, we need to subtract the total number of students who like either or both flavors from the total number of students:

Total number of students = 300

Number of students who like vanilla or chocolate = 258 + 142 = 400

Number of students who like both = 102

Number of students who like neither flavor = 300 - 400 + 102 = 2

Probability = 2/300 = 0.0067

C. To find the probability that a student likes vanilla ice cream but not chocolate ice cream, we need to subtract the number of students who like both from the total number of students who like vanilla:

Number of students who like vanilla = 142

Number of students who like both = 102

Number of students who like only vanilla = 142 - 102 = 40

Probability = 40/300 = 0.1333

User Barron
by
8.5k points