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How many moles of NH3 can be produced if 1.14 moles of H2 reacts completely with nitrogen?

N2 + 3 H2 --> 2 NH3

1 Answer

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Step-by-step explanation:

The balanced equation for the reaction is:

N2 + 3 H2 → 2 NH3

From the equation, we can see that 3 moles of H2 are needed to produce 2 moles of NH3.

Therefore, if 1.14 moles of H2 reacts completely, we can calculate the moles of NH3 produced as follows:

1.14 moles H2 × (2 moles NH3 / 3 moles H2) = 0.76 moles NH3

Therefore, 0.76 moles of NH3 can be produced if 1.14 moles of H2 reacts completely with nitrogen.

User Shadab K
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