Answer:If 7.48 moles of KClO3 are consumed, 11.22 moles of O2 will be produced.
Step-by-step explanation:
The balanced chemical equation for the reaction is:
2 KClO3 → 2 KCl + 3 O2
According to the stoichiometry of the balanced equation, for every 2 moles of KClO3 that react, 3 moles of O2 are produced. Therefore, the mole ratio of KClO3 to O2 is 2:3.
If 2 moles of KClO3 produce 3 moles of O2, then 1 mole of KClO3 will produce 3/2 = 1.5 moles of O2.
So, to find out how many moles of O2 will be produced when 7.48 moles of KClO3 are consumed, we can set up a proportion:
2 mol KClO3 / 3 mol O2 = 7.48 mol KClO3 / x mol O2
Solving for x, we get:
x = (3 mol O2 × 7.48 mol KClO3) / 2 mol KClO3
x = 11.22 mol O2
Therefore, if 7.48 moles of KClO3 are consumed, 11.22 moles of O2 will be produced.