The balanced chemical equation for the decomposition of potassium chlorate is:
2 KClO3(s) → 2 KCl(s) + 3 O2(g)
According to the equation, 2 moles of KCl are produced for every 2 moles of KClO3 that decompose. The molar mass of KClO3 is 122.55 g/mol, while the molar mass of KCl is 74.55 g/mol. Therefore, we can use the following steps to calculate the amount of KCl produced:
Calculate the number of moles of KClO3:
moles of KClO3 = mass of KClO3 / molar mass of KClO3
moles of KClO3 = 25 g / 122.55 g/mol
moles of KClO3 = 0.2036 mol
Use the mole ratio from the balanced equation to find the number of moles of KCl produced:
moles of KCl = moles of KClO3 x (2 moles of KCl / 2 moles of KClO3)
moles of KCl = 0.2036 mol x (2/2)
moles of KCl = 0.2036 mol
Calculate the mass of KCl produced:
mass of KCl = moles of KCl x molar mass of KCl
mass of KCl = 0.2036 mol x 74.55 g/mol
mass of KCl = 15.18 g
Therefore, 15.18 grams of potassium chloride are produced if 25 grams of potassium chlorate decompose.