Question

After rubbing two balloons against a sweater, each are held 0.75 meters apart. One balloon has a charge of 2.6 E−6 C. The other balloon has a charge of 2.2 E−7 C. Calculate the electrical force between them.

Remember to identify all data (givens and unknowns), list equations used, show all your work, and include units and the proper number of significant digits

Answer 1

Given:

Charge of balloon 1, q1 = 2.6 x 10^-6 C

Charge of balloon 2, q2 = 2.2 x 10^-7 C

Distance between the balloons, r = 0.75 m

Electric constant, k = 9 x 10^9 N m^2 C^-2

Unknown:

Electric force between the balloons, F

Formula:

Coulomb's Law: F = k * q1 * q2 / r^2

Substituting the given values into Coulomb's Law:

F = (9 x 10^9 N m^2 C^-2) * (2.6 x 10^-6 C) * (2.2 x 10^-7 C) / (0.75 m)^2

Simplifying the expression:

F = 6.05 x 10^-4 N

Therefore, the electric force between the two balloons is 6.05 x 10^-4 N, with three significant digits.

Answer 2

The electrical force between two charges can be calculated using Coulomb's law. In this case, the electrical force between two balloons with different charges is found using the formula F = k * (q1 * q2) / r^2. By plugging in the given values, the electrical force is found to be 6.38 * 10^-2 Newtons.

Step-by-step explanation:

The electrical force between two charges can be calculated using Coulomb's law. Coulomb's law states that the magnitude of the electrical force between two charges is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.

The formula for Coulomb's law is:

F = k * (q1 * q2) / r^2

Where:

• F is the electrical force
• k is the electrostatic constant (9 * 10^9 N*m^2/C^2)
• q1 and q2 are the charges of the two objects
• r is the distance between the two objects

Using the given values:

• q1 = 2.6 * 10^-6 C
• q2 = 2.2 * 10^-7 C
• r = 0.75 m

Plugging in these values into the formula, we can calculate the electrical force:

F = (9 * 10^9 N*m^2/C^2) * (2.6 * 10^-6 C * 2.2 * 10^-7 C) / (0.75 m)^2

F = 6.38 * 10^-2 N

Therefore, the electrical force between the two charges is 6.38 * 10^-2 Newtons.