4. To determine how many moles of NaOH are needed to make a 6 liters of a 3.0 M NaOH solution, we can use the formula:
moles = concentration (in M) x volume (in L)
Substituting the values given, we have:
moles = 3.0 M x 6 L = 18 moles of NaOH
Therefore, 18 moles of NaOH are needed to make a 6 liters of a 3.0 M NaOH solution.
5. To determine how many grams of NaOH are needed to make 4 liters of a 6.0 M NaOH solution, we can use the formula:
moles = concentration (in M) x volume (in L)
Then, we can use the molar mass of NaOH to convert moles to grams:
mass (in g) = moles x molar mass
The molar mass of NaOH is 40 g/mol.
Substituting the values given, we have:
moles = 6.0 M x 4 L = 24 moles of NaOH
mass = 24 moles x 40 g/mol = 960 grams of NaOH
Therefore, 960 grams of NaOH are needed to make 4 liters of a 6.0 M NaOH solution.