Question

Luis plays basketball for WVC. For the free throws, he makes the

shot 75% of the time. He must now attempt two free throws. Probability that Luis makes the first
shot is 0.75. The probability Luis makes the second shot is 0.75. The probability Luis makes the
second free throw given that he made the first is 0.85. Calculate the probability that Luis makes
both free throws.
Please write your answer as a decimal. Round your answer to the third decimal place.

Answer 1

the answer is 0.638 .

Answer 2

Let's use the conditional probability formula to calculate the probability that Luis makes both free throws:

P(both free throws) = P(makes first) * P(makes second | makes first)

We are given that:

P(makes first) = 0.75

P(makes second | makes first) = 0.85

So we can substitute these values in the formula:

P(both free throws) = 0.75 * 0.85

P(both free throws) = 0.6375

Therefore, the probability that Luis makes both free throws is 0.6375, or 0.638 rounded to the nearest thousandth.