Question

Solve each system using substitution.
3.25x - 1.5y = 1.25
13x - 6y = 10

Answer 1

Explanation:

`3.25x - 1.5y = 1.25 \quad (a)`

`13x - 6y = 10\quad\quad(b)`

Make
`y` the subject in
`(b):`

`13x - 6y = 10`

`6y=13x-10`

`y=(13)/(6) x-(5)/(3) \quad(c)`

Substitute
`(c)` into
`(a):`

`3.25x - 1.5((13)/(6) x-(5)/(3)) = 1.25 \quad \text{(I will change decimals to fractions)}`

`(13x)/(4) -(3)/(2) ((13x)/(6) -(5)/(3) )=(5)/(4) \quad\quad \text{(I will remove brackets)}`

`(13x)/(4) - (13x)/(4) +(5)/(2) =(5)/(4)`

`(5)/(2) =(5)/(4)`

This is ambiguous meaning the system does not have a solution.

(I confirmed this on Wolfram Alpha)