Question

Hector has a collection of nickels, dimes, and quarters totaling 122 coins. The number of dimes he has is 3 more than four times the number of nickels, and the number of quarters he has is 19 less than the number of dimes. How many coins of each kind does he have?

Answer 1

Answer: 15 nickels, 63 dimes, 44 quarters

Explanation:

x=number of nickels

4x+3=number of dimes

4x+3-19=number of quarters

Solve the following equation:

x+4x+3+4x+3-19=122

9x-13=122

x=15

Plug x back into the expressions:

Number of nickels=15

Number of dimes:

4(15)+3

63

Number of quarters:

4(15)+3-19

44