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If you measured out 49.93 mL of a 1.000 M sodium hydroxide solution, how many moles of sodium hydroxide would be present?

User Rishav
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1 Answer

5 votes

Answer: 0.0499 moles of sodium hydroxide

Step-by-step explanation:

We can determine the number of moles by using the Molarity equation:

Molarity = Moles / Volume (volume is always in Liters)

We have 2 out of 3 components of this equation

Molarity = 1.000 M

Volume = 49.93 mL / 1000 = 0.0499 L

So we rearrange the equation like the following:

Moles = Molarity x volume

= 1.000 Mx 0.0499 L

= 0.0499 moles of sodium hydroxide

User Oral
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