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The equation of a line is y=1/4x-2. What is the equation of the line that is parallel to the first line and passes through (4, –2)?

A. y=-4x+14
B. y=-1/4x-1
C. y=-4x+3
D. y=1/4x-3

User TamRock
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1 Answer

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Two parallel lines have the same slope, so we need to find the slope of the first line y = (1/4)x - 2, and then use it to find the equation of the parallel line that passes through (4, -2).

The slope of the first line is 1/4, so the slope of the parallel line will also be 1/4.

Using the point-slope form of the equation, we can write the equation of the parallel line as:

y - (-2) = (1/4)(x - 4)

Simplifying this equation, we get:

y + 2 = (1/4)x - 1

Subtracting 2 from both sides, we get:

y = (1/4)x - 3

Therefore, the equation of the line that is parallel to y = (1/4)x - 2 and passes through (4, -2) is y = (1/4)x - 3, which is option D.

User Tmarwen
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