Answer:
Part A
The volume of solution A is represented as a fraction, so we need to convert it to a decimal number. To do this, we set up a long division problem with the numerator (the top number in the fraction) as the dividend and the denominator (the bottom number in the fraction) as the divisor. So the dividend is 1, and the divisor is the volume of solution A.
Part B
No, we cannot divide 2 by 9 evenly because they are not divisible without a remainder.
Part C
Since we cannot divide 2 by 9 evenly, the first digit of the quotient will be 0.
Part D
We set up the long division problem as follows:
0.2 7 7 7 7 ...
-------------
9 | 1.0000
- 0.9
-----
1 0 0
9 0
---
1 0 0 0
9 0
-----
1 0 0 0
9 0
-----
1 0 0 0 0
9 0
-----
1 0 0 0 0
The decimal equivalent of 2/9 is 0.27777... (repeating). We can see that the division process continues indefinitely with the same repeating pattern, so we use an ellipsis to indicate that the pattern continues infinitely.
Part E
If we keep repeating the long division process for 2/9, we will continue to get the same repeating decimal pattern of 0.27777..., with no end in sight.
Part F
The volume of solution B is represented as the fraction 3/8, so we need to convert it to a decimal number. To do this, we set up a long division problem with the numerator (3) as the dividend and the denominator (8) as the divisor.
Part G
No, we cannot divide 3 by 8 evenly because they are not divisible without a remainder.
Part H
Since we cannot divide 3 by 8 evenly, the first digit of the quotient will be 0.
Part I
We set up the long division problem as follows:
0.3 7 5
---------
8 | 3.0000
- 2.4
----
6 0
5 6
---
4 0 0
3 2
---
7 0 0
6 4
---
3 6 0
3 2
---
2 8 0
2 4
---
4 0
The decimal equivalent of 3/8 is 0.375. We can see that the division process terminates after a finite number of decimal places.
Part J
If we keep repeating the division process for 0.375, we will always get the same decimal number because the process terminates and doesn't involve any repeating pattern.
Part K
The volume of solution C is represented as the fraction 1/5, so we need to convert it to a decimal number. To do this, we set up a long division problem with the numerator (1) as the dividend and the denominator (5) as the divisor.
Part L
No, we cannot divide 1 by 5 evenly because they are not divisible without a remainder.
Part M
Since we cannot divide 1 by 5 evenly, the first digit of the quotient will be 0.
Part N
We set