Question

3w^2-12w=-12
use quadratic formula to solve

Answer 1

w = 2

Explanation:

`3w^(2) -12w=-12\\3w^(2) -12w+12 = 0\\`

`\frac{-b + \sqrt{b^(2) - 4ac} }{2a}`

`\frac{-(-12) + \sqrt{(-12)^(2) - 4(3)(12) } }{2(3)} = 2`

Answer 2

To solve the quadratic equation 3w^2 - 12w = -12, we can use the quadratic formula:

x = (-b +/- sqrt(b^2 - 4ac)) / (2a)

In this case, a = 3, b = -12, and c = -12. Plugging these values into the formula, we get:

w = (-(-12) +/- sqrt((-12)^2 - 43(-12))) / (2*3)

Simplifying, we get:

w = (12 +/- sqrt(144 + 144)) / 6

w = (12 +/- sqrt(288)) / 6

w = (12 +/- sqrt(288)) / 6

w = (12 +/- 16.97) / 6

w = (12 +/- 16.97) / 6

w = 28.97/6 or -4.97/6

w = 4.828 or -0.828

Therefore, the solutions to the equation 3w^2 - 12w = -12 are w = 4.828 and w = -0.828.