Question

A 8.5L sample of gas was cooled from 31°C to –15°C. What is the final volume of the gas?

Answer 1

apply Charles formula

i.e; V1/T1= V2/T2

here V1= 8.5L

T1= 31°C

T2= -15°C

V2= ?

substitute the values in the above equation;

8.5/31=V2/(-15)

V2= 8.5/31x(-15)

V2= 0.2741x(-15)

V2= -4.11