Question

Please help solve this answer

Answer 1

Answer: Not quite sure what you wanted to do with this equation bet here it is multiplied

Explanation:

Answer 2

`((2x-1)(x+5))/(x+3)`

Explanation:

Given expression:

`(2x^2+7x-4)/(x^2+8x+15) \cdot (x^2+10x+25)/(x+4)`

Begin by factoring the numerator and denominator of the first fraction.

`\underline{\sf Numerator}\\\\\begin{aligned}\phantom{\implies} &2x^2+7x-4\\\implies &2x^2+8x-x-4\\\implies &2x(x+4)-1(x+4)\\\implies &(2x-1)(x+4)\end{aligned}`
`\underline{\sf Denominator}\\\\\begin{aligned}\phantom{\implies} &x^2+8+15\\\implies &x^2+3x+5x+15\\\implies &x(x+3)+5(x+3)\\\implies &(x+5)(x+3)\end{aligned}`

Now factor the numerator of the second fraction.

`\begin{aligned}\phantom{\implies} &x^2+10x+25\\\implies &x^2+5x+5x+25\\\implies &x(x+5)+5(x+5)\\\implies &(x+5)(x+5)\end{aligned}`

Rewrite the original expression with the factored polynomials:

`((2x-1)(x+4))/((x+5)(x+3)) \cdot ((x+5)(x+5))/(x+4)`

`\textsf{Apply the fraction rule:} \quad (a)/(c)\cdot(b)/(d)=(ab)/(cd)`

`((2x-1)(x+4)(x+5)(x+5))/((x+5)(x+3)(x+4))`

Cancel the common factors (x + 4) and (x + 5):

`((2x-1)(x+5))/(x+3)`