Question

In which of the given sets of numbers are all the numbers solutions of 9−2x≥3?(1 point)

Responses


4, 5, 6

4, 5, 6


3, 4, 5, 6

3, 4, 5, 6


0, 1, 3, 5

0, 1, 3, 5


0, 1, 2, 3

0, 1, 2, 3



HELP ME ASAP PLS

Answer 1

The correct answer is: 3, 4, 5, 6.

Explanation:

The correct answer is: 3, 4, 5, 6.

To check, we can substitute each number into the inequality:

When x = 3: 9 - 2(3) ≥ 3, which simplifies to 3 ≥ 3 (true)

When x = 4: 9 - 2(4) ≥ 3, which simplifies to 1 ≥ 3 (false)

When x = 5: 9 - 2(5) ≥ 3, which simplifies to -1 ≥ 3 (false)

When x = 6: 9 - 2(6) ≥ 3, which simplifies to -3 ≥ 3 (false)

Therefore, only the numbers in the set {3, 4, 5, 6} satisfy the inequality.