167k views
5 votes
find the equation of the straight line which is perpendicular to y= 1/2x+1 and passes through the point (2,2)

1 Answer

3 votes

Answer: (2,2) is y = -2x + 6.

Step-by-step explanation: The given equation is y = (1/2)x + 1.

The slope of this line is 1/2, which is also the slope of any line perpendicular to it is -2 (negative reciprocal of 1/2).

Using the point-slope form of the equation of a line, the equation of the line passing through (2,2) with slope -2 is:

y - y1 = m(x - x1)

where m = -2, x1 = 2, y1 = 2

y - 2 = -2(x - 2)

y - 2 = -2x + 4

y = -2x + 6

Hence, the equation of the straight line which is perpendicular to y= 1/2x+1 and passes through the point (2,2) is y = -2x + 6.

User Kizer Yakuza
by
7.5k points

No related questions found