Question

A negatively charged particle accelerates from East to West in a uniform electric field. What are the direction and the value of the electric field if the particle has charge q-3mC, mass m=1mg, the value of its acceleration is 3mm/s²? and if the value of its acceleration is 3mm/s²?​

Answer 1

Answer: 9 N/C.

Explanation: The direction of the electric field is from West to East.

We can use the equation for the acceleration of a charged particle in an electric field:

a = (q/m)E

where a is the acceleration of the particle, q is the charge on the particle, m is the mass of the particle, and E is the electric field.

Plugging in the given values, we have:

3 mm/s^2 = (-3 mC / 1 mg) * E

Simplifying and converting units, we get:

E = 9 N/C

Therefore, the direction and value of the electric field is from West to East with a magnitude of 9 N/C.