Answer:
B
Explanation:
assuming you mean
using the definition
n
=
where n! = n(n - 1)(n - 2) × 3 × 2 × 1
then
8
=
=
= (8 × 7 × 6 × 5 × 4 × 3 × 2 × 1) / (6 × 5 × 4 × 3 × 2 × 1 × 2 × 1
cancel (6 × 5 × 4 × 3 × 2 × 1 ) on numerator / denominator
= (8 × 7 ) / 2 × 1
= 56 ÷ 2
= 28
Apologies for formatting.